Programming 3 - 300 points
Description: So our folks wanted to work on binomial series but they understood incorrectly so they made a series of this type. if series is for 10 numbers
10/1 + 9/2 + 8/3 ..... 1/10 = 22.218 round to 2 decimal place = 22.21
now they did calculated this series for 31337 numbers can you help these guys in finding the number again.
public class Binomial {
static final int number=31337; // The binominal value that we are searching for based on the requirements.
/** * @param args the command line arguments */
public static void main(String[] args) {
// TODO code application logic here
double sum=0; // sum is declared and initialised with the value of zero.
for(int ctr=1;ctr<=number;ctr++)
{
sum=sum+(((number+1)-ctr)/ctr); // The method of calculation used.
// e.g. Term 1: sum=0+(((31337+1)-1)/1),
// Term 2: sum=31337+(((31337+1)-2)/2), ...,
//Term 31337: sum=311180.64640351594+(((31337+1)-31337)/31337)
}
System.out.printf("%.2f\n",sum); // Round off to two decimal places.
}
}
The flag is: 311180.65